(x^2+y)(2x-4)=

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Solution for (x^2+y)(2x-4)= equation: 


Simplifying
(x2 + y)(2x + -4) = 0

Reorder the terms:
(x2 + y)(-4 + 2x) = 0

Multiply (x2 + y) * (-4 + 2x)
(x2(-4 + 2x) + y(-4 + 2x)) = 0
((-4 * x2 + 2x * x2) + y(-4 + 2x)) = 0
((-4x2 + 2x3) + y(-4 + 2x)) = 0
(-4x2 + 2x3 + (-4 * y + 2x * y)) = 0

Reorder the terms:
(-4x2 + 2x3 + (2xy + -4y)) = 0
(-4x2 + 2x3 + (2xy + -4y)) = 0

Reorder the terms:
(2xy + -4x2 + 2x3 + -4y) = 0
(2xy + -4x2 + 2x3 + -4y) = 0

Solving
2xy + -4x2 + 2x3 + -4y = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(xy + -2x2 + x3 + -2y) = 0

Ignore the factor 2.

Subproblem 1
Set the factor '(xy + -2x2 + x3 + -2y)' equal to zero and attempt to solve:

Simplifying
xy + -2x2 + x3 + -2y = 0

Solving
xy + -2x2 + x3 + -2y = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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